Find the equation of a line that passes through the point (3,4) and has a gradient of 4.
Leave your answer in the form y= mx + c

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Answer:

y=4x-8

Step-by-step explanation:

Y=mx+c

4=4(3)+c

C=-8

y=4x-8

Step-by-step explanation:

given that gradient i.e. m= dy/dx = 4.

equation passes through point (3,4)...

(Y - y1) = m (X-x1)

Y-4 = 4(X-3)

Y-4 = 4X-12

or Y = 4X-8

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