please solve!!!!!!!!!!!!!!!!!!!!!!!
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Solution:
We know that:
[tex]\bullet \ \ \tex\text{Area of triangle:} = \frac{1}{2} \times \tex\text{Base} \times \tex\text{Height}[/tex]
Let the base of the triangle be 11 yd. If we extend the base, it will allow us to find the height of the triangle, which is 8 yd.
Using the formula:
[tex]\bullet \ \ \tex\text{Area of triangle:} = \frac{1}{2} \times 11 \times 8[/tex]
Now, let's simplify.
[tex]\bullet \ \ \tex\text{Area of triangle:} = \frac{1}{2} \times 11 \times 8[/tex]
[tex]\bullet \ \ \tex\text{Area of triangle:} = 11 \times 4[/tex]
[tex]\boxed{\bold{\tex\text{Area of triangle:} = 44 \ \tex\text{yd}^{2}}}[/tex]