Question

A powerlifter deadlifts a 365 lb (167 kg) barbell to a height of 0. 85 m, and then lowers the bar, applying a constant upward force. The bar reaches the ground with a speed of 2 m/s. What was the work done by the powerlifter in lowering the bar to the ground (in J)

Answer 1

When the powerlifter deadlifts a  167 kg barbell to a height of 0. 85 m, the work done by the powerlifter is mathematically given as

W=-1057.11J

What was the work done by the powerlifter in lowering the bar to the ground?

Question Parameters:

A powerlifter deadlifts a 365 lb (167 kg) barbell to a height of 0. 85 m,

The bar reaches the ground with a speed of 2 m/s

Generally, the equation for the work done  is mathematically given as

W=0.5mvf^2+mghf)-(0.5mv1^2+mghi)

Therefore

W=0.5*16*167*2^2-(167*9.8*0.85)

W=-1057.11J

In conclusion, work done is

W=-1057.11J

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