Question

A 0. 105 kg hockey puck is traveling at 12 m/s when it is struck by a stick. As a result, the puck travels at 15

m/s in the opposite direction. If the contact between the stick and puck lasted 0. 05 s, what was the force?


A 400 kg jet dragster's engine produces 5500 N of thrust. If the dragster starts from rest, how fast will it be

moving after 1. 5 s? After 3 s?


A loaded barge has a mass of 1 500 000 kg and is traveling at 3 m/s. If a tugboat applies an opposing force

of 12 000 N for 10 s, what is its final velocity? How long will it take to stop the barge? How much force

would a tugboat need to apply to stop it in one minute?


An Airbus A380 airliner lands at 30 m/s. Partially loaded, its mass is 480 000 kg. The engines app ly reverse

thrust for 12 s to slow the plane to 25 m/s. How much thrust did the engines apply?

Answer 1

(1) The force of the hockey puck is 6.3 N.

(2) The speed of the jet engine after 1.5 s 20.63 m/s and after 3 it is 41.25 m/s.

(3) The final velocity of the loaded barge is 2.92 m/s.

(4) The thrust applied by the engine 600,000 N.

1.0 Force of the hockey puck

The force of the hockey puck is calculated as follows;

F = ma

F = mv/t

F = 0.105 x (15 - 12)/0.05

F = 6.3 N

2.0 Speed of the jet Engine

F = mv/t

mv = Ft

v = Ft/m

Velocity after 1.5 s

v = (5500 x 1.5)/400

v = 20.63 m/s

Velocity after 3 s = 2v = 41.25 m/s

3.0 Final velocity of the loaded barge

F = m(v - u)/t

m(u - v) = Ft

u - v = Ft/m

u - v = (12000 x 10)/1500000

u - v = 0.08

v = u - 0.08

v = 3 - 0.08

v = 2.92 m/s

4.0 Thrust applied by the engine

F = m(v - u)/t

F = 480,000(30 - 15)/12

F = 600,000 N

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