The profit function of the business is the difference between the revenue and the cost functions
- The equations of the cost and the revenue functions are: [tex]y = \frac 43x[/tex] and [tex]y = 0.5x + 3.5[/tex]
- The profit function is [tex]y = \frac 56x - 3.5[/tex]
- The profit after 10 months of operation is 29/6
Part A: The equations to represent the functions
For the revenue function, we have the following points
(x,y) = (0,0) and (6,8.0)
Since the line passes through the origin, the equation of the line would be:
[tex]y = \frac{y_1}{x_1} * x[/tex]
So, we have:
[tex]y = \frac{8.0}{6} * x[/tex]
[tex]y = \frac 43x[/tex]
For the cost function, we have the following points
(x,y) = (0,3.5) and (9,36) for x > 5
The equation of the line would be:
[tex]y = \frac{y_1-y_2}{x_1-x_2} * (x - x_1) + y_1[/tex]
So, we have:
[tex]y = \frac{6.5-3.5}{6-0} * (x - 0) + 3.5[/tex]
[tex]y = 0.5x + 3.5[/tex]
Hence, the equations of the cost and the revenue functions are: [tex]y = 0.5x + 3.5[/tex] and [tex]y = \frac 43x[/tex]
Part B: The profit function
This is calculated as:
Profit = Revenue - Cost
So, we have:
[tex]y = \frac 43x - 0.5x - 3.5[/tex]
Evaluate the difference
[tex]y = \frac 56x - 3.5[/tex]
Part C: The profit after 10 months of operation
Substitute 10 for x in [tex]y = \frac 56x - 3.5[/tex]
[tex]y = \frac 56 * 10 - 3.5[/tex]
[tex]y = \frac {50}6 - 3.5[/tex]
Evaluate the difference
[tex]y = \frac {50-21}6[/tex]
[tex]y = \frac {29}6[/tex]
Hence, the profit after 10 months of operation is 29/6
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