PLEASE HELP! I can’t figure this out.
Find M.
![PLEASE HELP I cant figure this out Find M class=](https://us-static.z-dn.net/files/de9/aaae6ec6612ac9e04a8359a660813c8e.png)
[tex] \gray \bigstar \boxed{\angle 1 + \angle 2 + \angle 3= 180°}[/tex]
Reason :-
Sum of angles of triangle is equal to 180°
Formula :-
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So:-
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[tex] \sf \dashrightarrow\angle 1 + \angle 2 + \angle 3= 180 \degree[/tex]
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[tex] \sf \dashrightarrow m + 3m +(m - 35) = 180 \degree[/tex]
[tex] \\ \\ [/tex]
[tex] \sf \dashrightarrow m + 3m +m - 35= 180 \degree[/tex]
[tex] \\ \\ [/tex]
[tex] \sf \dashrightarrow 4m +m - 35= 180 \degree[/tex]
[tex] \\ \\ [/tex]
[tex] \sf \dashrightarrow 5m - 35= 180 \degree[/tex]
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[tex] \sf \dashrightarrow 5m= 180 \degree + 35 \degree[/tex]
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[tex] \sf \dashrightarrow 5m=215\degree[/tex]
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[tex] \sf \dashrightarrow m= \dfrac{215}{5} \degree[/tex]
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[tex] \sf \dashrightarrow m= \cancel \dfrac{215}{5} \degree[/tex]
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[tex] \bf \dashrightarrow m=43 \degree[/tex]
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Verification :-
[tex] \\ [/tex]
[tex] \sf \dashrightarrow m + 3m +(m - 35) = 180 \degree[/tex]
put value of m
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[tex] \sf \dashrightarrow 43 + 3(43) +(43 - 35) = 180 \degree[/tex]
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[tex] \sf \dashrightarrow 43 + 3(43) +(8) = 180 \degree[/tex]
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[tex] \sf \dashrightarrow 43 + 3(43) +8= 180 \degree[/tex]
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[tex] \sf \dashrightarrow 43 +129+8= 180 \degree[/tex]
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[tex] \sf \dashrightarrow 43 +137= 180 \degree[/tex]
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[tex] \bf \dashrightarrow 180 \degree= 180 \degree[/tex]
LHS = RHS
Hence verified!