NO LINKS!! Part 8: Please help me with this problem
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Answer:
Step-by-step explanation:
in 10 hrs distance covered=speed×time=15×10=150 nautical miles.
x²=600²+150²-2×600×150×cos 20°
x²=360,000+22,500-180,000×cos 20°
x=√(382,500+180,000×cos 20°)
x\approx 742.73 nautical miles
time taken=742.73/15 \approx ~49.52 hours
total time taken=10+49.52=59.52 hours
applying sine formula
[tex]\frac{sin ~B}{150} =\frac{sin~20}{742.73} \\\sin~B=\frac{150}{742.73} \times~sin~20\\B=\sin^{-1} [\frac{150}{742.73} \times \sin~20]\\B\approx~3.96 ^\circ\\B\approx 4^\circ[/tex]
so it has to make a turn=20+4=24°