An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment. Compute the probability of each of the following events. Event A: The sum is greater than 6. Event B: The sum is not divisible by 3. Write your answers as fractions.

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Answer:

11

Step-by-step explanation:

if 6+5  and its not divisblibe by 3

The probability of the sum being greater than 6 will be 7/12. And the probability of the sum is not divisible by 3 will be 1/3.

What is probability?

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots).

Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together.

This sum is recorded as the outcome of a single trial of a random experiment.

The number of the total events will be

Total events = 6 x 6

Total events = 36

The total sample is given below.

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

The probability of the sum is greater than 6 will be

Favorable events = 21

P = 21 / 36

P = 7/12

The probability of the sum is not divisible by 3 will be

Favorable events = 21

P = 12 / 36

P = 1/3

More about the probability link is given below.

https://brainly.com/question/795909

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