Answer:
Step-by-step explanation:
In ΔABC & ΔCDA
AB ≅ CD Given
BC ≅ AD Given
AC ≅ CA Reflexive property
ΔABC ≅ ΔCDA SSS congruent
⇒ ∠B =∠D CPCT {Corresponding parts of congruent triangles}
Now, join BD.
In ΔBAD & ΔBCD
AB ≅CD Given
AD ≅ BC Given
BD ≅ DB Reflexive property
ΔBAD ≅ ΔBCD SSS congruent
