Question

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.​

Answer 1

Answer:

$\textsf{area of a sector}=\dfrac{\theta\pi r^2}{360\textdegree} \mathsf{\ \ (where\ \theta \ is\ in\ degrees)}$

Given:

• radius (r) = 6 cm
• $\theta$ = 60°

$\implies \textsf{area}=\dfrac{60\textdegree \times\pi \times 6^2}{360\textdegree}$

$\implies \textsf{area}=\dfrac{2160\pi}{360}$

$\implies \textsf{area}=6\pi \textsf{ cm}^2$

$\implies \textsf{area}=18.85\textsf{ cm}^2 \textsf{ (nearest hundredth)}$