Solve for x. Leave your answer in simplest radical form.
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Answer:[tex]2\sqrt{3}[/tex]
Step-by-step explanation:
Use pytha. theorem on leftmost triangle and get sqrt(13)
Use it again on the other triangle: 13+b^2=25
First, we find the hypotenuse of the first triangle
(Use the pythagorean theorem) : [tex]3^{2} + 2^{2} = 9 + 4 = 13[/tex]
So, the length of the side = [tex]\sqrt{13}[/tex]
Now, we find x :
x(squared) = [tex]5^{2} -\sqrt{13} ^{2}[/tex] = 25 - 13 = 12
-> x = [tex]\sqrt{12}[/tex] = 2[tex]\sqrt{3}[/tex]