Respuesta :

  • This is Right Angled Triangle.

Solution :

  • We'll solve this using the Pythagorean Theorem

Let,

  • Let AB be Base.

  • 4 be BC, where BC is the Perpendicular.

  • 5 be AC, where AC is the Hypotenuse.

We know that,

[tex]{ \longrightarrow \bf \qquad \: (AB) {}^{2} +( BC) {}^{2} = (AC) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} +( 4) {}^{2} = (5) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} = (5) {}^{2} - ( 4) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{(5) {}^{2} - ( 4) {}^{2}} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{25 - 16 }}[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{9 }}[/tex]

[tex]{ \longrightarrow {\pmb {\bf\qquad \: AB = 3}}}[/tex]

Therefore,

  • The length of the third side is 3 .
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