Question

Find the length of the third side. If necessary, round to the nearest tenth 22 25

Answer 1

• This is Right Angled Triangle.

Solution :

• We'll solve this using the Pythagorean Theorem.

Let,

• Let BC be perpendicular.

• 22 be AB, where AB is the Base.

• 25 be AC, where AC is the Hypotenuse.

We know that,

${ \longrightarrow \bf \qquad \: (AB) {}^{2} +( BC) {}^{2} = (AC) {}^{2} }$

${ \longrightarrow \sf \qquad \: (22) {}^{2} +( BC) {}^{2} = (25) {}^{2} }$

${ \longrightarrow \sf \qquad \: (BC) {}^{2} = (25) {}^{2} - ( 22) {}^{2} }$

${ \longrightarrow \sf \qquad \: BC = \sqrt{(25) {}^{2} - ( 22) {}^{2}} }$

${ \longrightarrow \sf \qquad \: BC = \sqrt{625 - 484} }$

${ \longrightarrow \sf \qquad \: BC = \sqrt{141} }$

${ \longrightarrow \bf \qquad \: BC \approx11.87 }$

Therefore,

• The length of the third side is 11.9 (Nearest tenth of 11.87) .

Answer 2

Step-by-step explanation:

According to Pythagoras theorem ,

Hypotenuse² = Perpendicular ² + Base ²

Here , we have to find perpendicular

• Hypotenuse = 25 unit
• Base = 22 unit

So,

Hypotenuse² - Base² = Perpendicular²

putting the known values

25² - 22² = perpendicular²

141 = perpendicular²

√141 = perpendicular

Perpendicular = 11.9 unit