Consider the inequality first ;
[tex]{:\implies \quad \sf 2x-2\> 2x+4}[/tex]
Subtracting 2x from both sides ;
[tex]{:\implies \quad \sf \cancel{2x}-2-\cancel{2x}\> \cancel{2x}+4-\cancel{2x}}[/tex]
[tex]{:\implies \quad \sf -2\> 4}[/tex]
But , as the given situation isn't possible in mathematics , so the inequality have no solutions . Or [tex]{\bf{x\in \phi}}[/tex] , where [tex]\bf \phi[/tex] is the empty set.
