Question

Resistor 1 has twice the resistance of resistor 2. They are connected in parallel to a battery. The ratio of the thermal energy dissipation by 1 to that by 2 is:

Answer 1

The ratio of the thermal energy dissipation by resistor 1 to that by resistor 2 will be  1 : 2

The Resistance of a Resistor

Resistors can be arranged in series or parallel

The resistors arranged in parallel will have the same potential difference across each every one of them.

Given that Resistor 1 has twice the resistance of resistor 2. They are connected in parallel to a battery. That is

$R_{1}$ = 2$R_{2}$

Power P = lV

from Ohm's law

V = lR

Make l the subject of formula

l = V/R

Substitute l into power formula

P = $V^{2}$ / R

For the Resistor 1,

P =  $V^{2}$ / 2$R_{2}$

For the Resistor 2

P =  $V^{2}$ / $R_{2}$

The ratio of the thermal energy dissipation by 1 to that by 2 will be

$V^{2}$/2$R_{2}$ x $R_{2}$/$V^{2}$

The $V^{2}$ and the $R_{2}$ will cancel out.

Therefore, the ratio of the thermal energy dissipation by 1 to that by 2 will be  1:2

Learn more about Resistance here: https://brainly.com/question/24858512