Question

A helium atom has a diameter of about 0.000000000062 meters. The diameter of the sun is about
1,400,000,000 meters. Express the diameter of each in scientific notation. About many times larger is
the diameter of the sun than the diameter of a helium atom?

Answer 1

Step-by-step explanation:

diameter of the sun divides the diameter of an helium atom.

helium atom = 0.000000000062 = 6.2 × 10^-11

Sun = 1,400,000,000 = 1.4 × 10^9

$\frac{1.4 \times 10 {}^{ 9} }{6.2\times 10 {}^{ - 11} }$

$\frac{1.4}{6.2} \times 10 {}^{9 + 11}$

$0.225 \times 10 {}^{20}$

so therefore the diameter of the sun is 0.225 × 10^20 times bigger than the nucleus of an helium atom