Question

A 85 kg skydiver parachutes from a stationary helicopter at a height of 1,200 m above the ground. After the
skydiver reaches a predetermined speed, the parachute opens, slowing the skydiver down. With the parachute
open, the skydiver reaches a terminal velocity of 3.5 m/s.
Calculate the work done by air resistance during the descent from the height of the helicopter to the ground.

Answer 1

The work done by air resistance during the descent from the height of the helicopter to the ground is 520.2 J.

Acceleration of the skydiver

The acceleration of the skydiver is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

v² = 2as

a = (v²)/(2s

a = (3.5²)/(2 x 1200)

a = 0.0051 m/s²

Work done by air resistance

W = Fd

W = (ma)d

W = (85 x 0.0051) x 1200

W = 520.2 J

Thus, the work done by air resistance during the descent from the height of the helicopter to the ground is 520.2 J.

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