Question

Hello! I’d appreciate if you guys can help me with this. Thank you! :)

Answer 1

Answer:

x=2

Step-by-step explanation:
Part 1:

$\sqrt{4x-3}=5$
First we can square both sides to remove the square root symbol:

$(\sqrt{4x-3})^{2} =(5)^{2}$

Simplify:

$4x-3=5$

Add 3 to both sides and simplify:

$4x=8$

Divide both sides by 4 and simplify to find x:

x=2

Part 2:

Extraneous solutions are values that we get when solving equations that aren't really solutions to the equation.

If we substitute 2 into the equation we get:

$\sqrt{4(2)-3} =5$

Simplify to get:

$\sqrt{8-3} =5$

$\sqrt{5} =5$ WHICH IS INCORRECT

Therefore the solution is extraneous