Question

The temperature last Monday was 32°F at 8:00 AM during the next hour it dropped to 26°F.

What was the percent of change

(you can round to the nearest percent or leave the decimal in the percent.)



Please show how you found the answer and put the overall answer thank you



(Giveing Brainly Ian worth 50 points)

Answer 1

Answer:

18.75% change

explanation:

• initial temperature =  32°F

• final temperature = 26°F

change:  32°F - 26°F = 6°F

$\sf change \ in \ percentage \ : \ \dfrac{6}{32} *100 \ \rightarrow 18.75 \%$  

Answer 2

• Initial temperature=32°F
• Final temperature=26°F

Rate of change:-

• ∆T=32-26=6°F

Percentage

$\\ \rm\rightarrowtail \dfrac{6}{32}(100)$

$\\ \rm\rightarrowtail 0.1875(100)$

$\\ \rm\rightarrowtail 18.75\%$