Question

A racing car can be slowed with a deceleration of -11 m/s2. If it is moving with 55 m/s. How far will it travel to stop, express your answer in scientific notation?.

Answer 1

Answer: 137.5m

Explanation:

We are given the acceleration, the initial velocity, and implicitly given the final velocity. It wasn't stated, but the final velocity is zero. The car will eventually come to a stop. We can use the kinematic formula below to find the displacement given the initial conditions:

$v_f^2=v_i^2+2ad$

$0^2=55^2+2(-11)(d)$

$-55^2=-22d$

$55^2=22d$

$3025=22d$

$d=137.5m$