Question

I'LL MARK BRAINLIEST ITS URGENT
An object in the shape of a cube with dimensions a= 14m, should be painted on 5 sides, and the bottom should not be painted. If 2 square meters can be painted with 1 liter of paint, and the paint is packed in 5 liter bins, how many bins will be needed?

Answer 1

Answer: 98 bins

Step-by-step explanation:

First, we should find the surface area of the cube at which can be painted. A cube has six sides, and we can only paint five of the sides.

Lets find the area of a single side, then multiply that value by 5 to compensate for the number of sides. The area of a square is the side of the square squared. Therefore we have:

$Area=a^2$

$Area=(14m)^2=196m^2$

Multiply the area of one side by 5 to get:

$Area=(196m^2)*(5)=980m^2$

This means we have 980 square meters to paint. One singular bin is said to have 5 cans of paint. It was also said that 1 single can of paint is able to cover 2 square meters of surface. Before seeing how many bins of paint we need, lets first find how many containers of paint we need. Dividing 980 square meters by 2 square meters, we obtain:

$980m^2/2m^2=490$

We need 490 cans of paint. One singular bin has 5 cans of paint. Divide 490 by 5 to get:

$490/5=98$

We need 98 bins of paint, where each bin contains 5 cans of 1 liter paint.