Taking into account the reaction stoichiometry and the definition of molarity, the concentration of KMnO₄ is 0.053 [tex]\frac{moles}{liter}[/tex].
In first place, the balanced reaction is:
2 KMnO₄ + Na₂C₂O₄ → K₂C₂O₄ + 2 NaMnO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case, you know:
Replacing in the definition of molarity:
[tex]0.03105 M=\frac{number of moles}{0.025 L}[/tex]
Solving:
0.03105 M× 0.025 L= number of moles
0.00077625 moles= number of moles
Then 0.00077625 moles of Na₂C₂O₄ react.
The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂C₂O₄ react with 2 moles of KMnO₄, 0.00077625 moles of Na₂C₂O₄ react with how many moles of KMnO₄?
[tex]moles of KMnO_{4} =\frac{0.00077625 moles of Na_{2} C_{2} O_{4} x 2moles of KMnO_{4}}{1 mole of Na_{2} C_{2} O_{4}}[/tex]
moles of KMnO₄= 0.0015525 moles
Finally, 0.0015525 moles of KMnO₄ is required to react with 0.00077625 moles of Na₂C₂O₄.
You know:
Replacing in the definition of molarity:
[tex]molarity=\frac{0.0015525 moles }{0.02911 L}[/tex]
Solving:
molarity= 0.053 [tex]\frac{moles}{liter}[/tex]
Finally, the concentration of KMnO₄ is 0.053 [tex]\frac{moles}{liter}[/tex].
Learn more about
the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
molarity:
brainly.com/question/9324116
brainly.com/question/10608366
brainly.com/question/7429224
