Question

Factor by grouping.

12x+12y+bx+by

Answer 1

Answer: (12+b)(x+y)

Step-by-step explanation:

The terms 12x and 'bx' share a common factor of 'x'. Therefore, we can group them together. The terms 12y and 'by' also share a term of 'y', so we can group them together too:

$12x+12y+bx+by$

$12x+bx+12y+by$

Factor out an 'x' from the first two terms to get:

$x(12+b)+12y+by$

Now, factor out a 'y' from the last two terms to get:

$x(12+b)+y(12+b)$

Since the quantities inside of the parenthesis are the exact same, we can also factor out the entire term (12+b) to get:

$(12+b)[x+y]$

Answer 2

$\\ \rm\rightarrowtail 12x+12y+bx+by$

• Take 12 common

$\\ \rm\rightarrowtail 12(x+y)+bx+by$

• Take b common

$\\ \rm\rightarrowtail 12(x+y)+b(x+y)$

$\\ \rm\rightarrowtail (12+b)(x+y)$