The concentration of bicarbonate ions is mathematically given as
H2CO3^- =9.27*10^{-5}m
Question Parameters:
HCO3-, in a 0. 010 m H2CO3 solution that has the stepwise dissociation constants
ka1 = 4. 3 × 10-7 and
ka2 = 5. 6 × 10-11
Generally, the equation for the Chemical Reaction is mathematically given as
H2CO3 ----><----HCO3^-+H+
Therefore
[tex]Ka1=\frac{HCO3^- +H^+}{H2CO3}[/tex]
[tex]Ka1=\frac{ca.ca}{c(1-a)}[/tex]
ca=HCO3^-
[tex]ca=\sqrt{4.3*10^{-7}*0.02}[/tex]
HCO3^-=9.27*10^{-5}m
On the second ionization of carbon
H2CO3 ----><----CO3^2-(aq) + H+(aq)
Where
1-a=1+a=1
In conclusion, the concentration of bicarbonate ions is
H2CO3^- =9.27*10^{-5}m
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