In the given reaction, the Copper(Cu) element is getting oxidized and the Nitrogen(N) element is getting reduced.
Any chemical reaction in which the oxidation number of a participating chemical species changes is called a redox reaction. Redox reaction is also called oxidation-reduction reaction. The formation of hydrogen fluoride is an example of a redox reaction.
The given reaction occurs as
[tex]\rm Cu+HNO_3 \rightarrow Cu(NO_3)_2 + NO + H_2O[/tex]
The given reaction is an example of a redox reaction.
A balanced chemical equation is:
[tex]\rm 3Cu+8HNO_3 \rightarrow 3Cu(NO_3)_2 + 2NO + 4H_2O[/tex]
Now, we write the oxidation number of chemical species involved in the reaction as
[tex]\rm3 \overset{0}Cu + 8\overset{+1}H\overset{+5}N\overset{-2}{O_3} \rightarrow 3\overset{+2}Cu(NO_3)_2 + 2\overset{+2}NO + 4H_2O[/tex]
From the above reaction, we can say that,
the oxidation number of the copper element(Cu) increases from [tex]0 \to +2[/tex]
the oxidation number of the nitrogen element(N) decreases from [tex]+5\to+2[/tex]
We know that,
Oxidation: increase in oxidation number
Reduction: decrease in oxidation number
So, from the above, we can conclude that, in the given reaction, the copper element(Cu) is getting oxidized and the nitrogen element(N) is getting reduced.
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