The equation at the vertex (2,6) will be given by [tex]F[x]=2|x-2|+6[/tex]
It is given that
vertex =(2,6)
The quadratic equation in the form of Vertex will be
[tex]y=a(x-h)^2+k[/tex]
Now here [tex](h,k)=(2,6)[/tex]
Now putting the values
[tex]y=a|x-2|^2+6[/tex]
Thus the function will be
[tex]F[x]=2|x-2|+6[/tex]
Thus equation at the vertex (2,6) will be given by [tex]F[x]=2|x-2|+6[/tex]
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