Question

a 100 kg crate,sliding on a floor, is brought to a stop by 25 N force what is the deceleration of the crate

Answer 1

Explanation:

a = ?

m = 100kg

Force = 25N

F = ma

a = F/m

a = 25/100

a = ¼

a = 0.25ms—²

deceleration = negative acceleration

deceleration = —0.25ms—²

Answer 2

Answer:

25neuton+100kg =125kg floor sliding