Question

A cricketer throws a ball to a team mate such that it is caught at the same height it was thrown 1. 6 s later. What was the maximum height to which the cricket ball rose?

Answer 1

This question involves the concepts of projectile motion.

The maximum height to which the ball rose is "3.14 m".

PROJECTILE MOTION

The motion of an object in both x and y axes simultaneously is known as projectile motion. The total time of flight of the projectile is given by the following formula:

$T=\frac{2v_oSin\theta}{g}\\\\v_oSin\theta=\frac{Tg}{2}$

where,

• T = time of flight = 1.6 s
• g = acceleration due to gravity = 9.81 m/s²

Therefore,

$v_oSin\theta = \frac{(1.6\ s)(9.81\ m/s^2)}{2}\\\\v_oSin\theta = 7.848\ m/s$

Now, using the formula for the maximum height of the projectile, we get:

$H=\frac{v_o^2Sin^2\theta}{2g}\\\\H= \frac{(7.848\ m/s)^2}{2(9.81\ m/s^2)}$

H = 3.14 m

Learn more about projectile motion here:

https://brainly.com/question/11049671