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The image formed is 2.4 cm from the lens
The height of the image is 7.2 cm.
This shows that the image is upright.
The lens used is a concave lens.
The height of the object, (h) is 9 cm
Object distance from the lens (u) is 3 cm
The focal length (f) of the lens is -12 cm
we have to find the image distance (v) from the lens and magnification factor.
"what mirror formula and what is the magnification?"
Suppose an object is placed u cm in front of a spherical mirror of focal length f such that the image is formed v cm from the mirror, then u, v, and f are related by the equation;
Magnification of a lens is defined as the ratio of the height of an image to the height of an object.
It is also given in terms of image distance and object distance.
It is equal to the ratio of image distance to that of object distance.
Using mirror's formula
1/f= 1/u + 1/v
1/(-12) = 1/(3) +1/(v)
1/(v) = (-5)/12
v = -2.4 cm
The image formed is 2.4 cm from the lens.
Magnification (m) = [tex]\\\dfrac{Height \ of Image (h') }{Height\ of\ Object (h) }[/tex]
[tex]Magnification\ (m) =\dfrac{-v}{u}[/tex]
[tex]h' =\dfrac{(-v)(h)}{u}[/tex]
[tex]h' =\dfrac{(-(-2.4))(9)}{3}[/tex]
h' = 7.2 cm
The height of the image is 7.2 cm. This shows that the image is upright.
The lens used is a concave lens.
Learn more about Concave lens
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