Question

A 1.04-kg binder is initially at rest on a wood desk. The binder is then pushed with a
constant force of 4.2 N. Friction with a magnitude of 1.8 N is exerted on the moving
binder by the surface of the desk. Draw an energy bar chart of the situation. Then
determine the final velocity of the binder after it has been pushed 0.70 meters across
the table.

Answer 1

The final velocity of the binder is 1.8 m/s.

Net force of the binder

The force of the binder is calculated as follows;

∑F = ma

F - Ff = ma

4.2 - 1.8 = 1.04(a)

2.4 = 1.04a

a = 2.4/1.04

a = 2.31 m/s²

Final velocity of the binder

The final velocity of the binder is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

v² = 2as

v² = 2(2.31) x 0.7

v² = 3.234

v = √3.234

v = 1.8 m/s

Thus, the final velocity of the binder is 1.8 m/s.

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