Question

1 An object rests on a rough surface and is pushed horizontally with force of 6 N.
The mass of the object is 5 kg and the coefficient of friction between the object and
the surface is 0.3.

1)The horizontal force acting on the object is increased to PN. Find the largest
value of P for which the object does not slip.

Answer 1

The normal force acting on the body is 49.05N

Data;

• force = 6N
• mass = 5kg
• coefficient of friction = 0.3

Horizontal Force

To calculate the horizontal force or the force acting on the horizontal plane on the body is given as

$N + fsin\theta = mg$

Where N = normal force

Let's substitute the values and solve.

$N = mg - fsin\theta\\N = (5 * 9.81) - 6 sin (0)\\N = 49.05N$

The normal force acting on the body is 49.05N

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