Question

A tabletop in the shape of a trapezoid has an area of 7,205 square centimeters. Its longer base measures 135 centimeters, and its shorter base is 85 centimeters. What is the height?

Answer 1

Given :

• Base = 135 cm and 85 cm.
• Area = 7205 cm².

To find :

• The height.

Solution :

We know,

${\qquad \dashrightarrow{ \bf \dfrac{1}{2 } \times (b_{1} + b_{2}) \times h = {Area_{(Trapezoid)} } }}$

Now, Substituting the values :

${\qquad \dashrightarrow{ \sf \dfrac{1}{2 } \times (135+ 85) \times h =7205 {} } }$

${\qquad \dashrightarrow{ \sf \dfrac{1}{2 } \times 220 \times h =7205 {} } }$

${\qquad \dashrightarrow{ \sf \dfrac{1}{ \cancel{2} } \times \cancel{ 220} \times h =7205 {} } }$

${\qquad \dashrightarrow{ \sf 110 \times h =7205 {} } }$

${\qquad \dashrightarrow{ \sf h = \dfrac{7205}{110} {} } }$

${\qquad \dashrightarrow{ \bf h =65.5 {} } }$

Therefore,

• The height of the tabletop in the shape of a trapezoid is 65.5 cm .