Question

The distance between slits on a diffraction grating is 0. 60 mm, and one of the angles of diffraction is 0. 30°. The light forms a second-order bright band. How large is the path difference? 1047 nm 1571 nm 3142 nm 6284 nm.

Answer 1

The path difference will be 1571 nm

What will be the path difference?

Now for the constructive interference, the formula is given

$\rm dsin\theta==n\lambda$

here,

d = is the distance between slits.=060mm

θ = is the angle of diffraction=0.30 Degree

n = is the order of fringe=2

λ = is the path difference.

$\lambda=\dfrac{(dsin\theta)}{n}$ $\lambda=\dfrac{(0.60\times10^{-3}\times sin(0.30)}{2} = 1.57\times10^{-6}$  

Thus path difference will be 1571 nm

To know more about the Diffraction of light follow

https://brainly.com/question/16749356

Answer 2

The answer is C. 3142