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In the diagram ABC and ADE are straight lines.
BD is parallel to CE.

AB = 9 cm, BC = 13.5 cm, AD = 10 cm, BD = 17 cm

Calculate the length of CE.

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Class 10>>Maths>>Triangles>>Basic Proportionality Theorem (Thales Theorem)>>In the adjoining figure, DE || AB, AD =

Question

In the adjoining figure, DE || AB, AD = 7 cm, CD = 5 cm and BC = 18 cm. Find BE and CE.

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Solution

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The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that DE∣∣AB,AD=9cm, CD=5 cm and BC=13.5 cm.

Using the basic proportionality theorem, we have

CACD=ABDE=CBCE

⇒CACD=CBCE

⇒125=18CE

⇒18×5=12CE

⇒12CE=90

⇒CE=1290=7.5

Since CE=7.5 cm, therefore,

CB=CE+EB

⇒18=7.5+EB

⇒EB=17−7.5=9.5

Hence, BE=10.5 cm and 

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