Respuesta :

Answer:

[tex]\huge\boxed{\bf\:x = 12, \:3}[/tex]

Step-by-step explanation:

[tex]x - 6 = \sqrt{3x}[/tex]

By squaring on both the sides,

[tex](x - 6)^{2} = (\sqrt{3x} )^{2}\\[/tex]

Now simplify it using the algebraic identity ⟶ (x - y)² = x² - 2xy + y². Also remember that when we square a square root the root in it will get removed.

[tex]x^{2} - (2*x *6) + 6^{2} = 3x\\x^{2} - 12x + 36 = 3x\\x^{2} + 36 = 3x + 12x\\x^{2} + 36 = 15x[/tex]

We can change the result into the following form [tex]\downarrow[/tex]

[tex]x^{2} + 36 - 15x = 0\\x^{2} - 15x + 36 = 0[/tex]

Now, this is in the standard form of a quadratic equation. Let's solve this further by using the splitting-the-middle-term method.

[tex]x ^ { 2 } -15x+36=0\\x^{2} - 12x - 3x + 36 = 0\\x(x - 12) - 3 (x - 12) = 0\\(x - 12)(x - 3) = 0[/tex]

Then, the values of x are:

[tex](x - 12) = 0\\\boxed{x = 12}\\\\\\(x - 3) = 0\\\boxed{x = 3}[/tex]

[tex]\rule{150}{2}[/tex]

Standard Form of a Quadratic Equation:

  • ax² + bx + c = 0
  • Here, a, b & c are the constants of the equation.

Splitting-the-middle-term Method:

  • It's also known the factorisation or factor by grouping method.
  • In this method, we need to factorise the middle term to solve the equation.

[tex]\rule{150}{2}[/tex]

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