The net work done by the Nitrogen in lifting the mass and the pressure is; W_n = 0.6257 kJ
We are given;
Mass of argon; m_a = 0.1 kg
mass of piston; m_p = 5 kg
Pressure 1; p₁ = 100 kPa
Temperature 1; T₁ = 300 K
Temperature 2; T₂ = 320 K
Ideal gas constant; R = 0.208 kJ/kg.K
γ = 1.67
Since the reaction is adiabatic and slowly reversible, then we will use the formula; PV^(γ) = C
Thus, work done by argon is;
W_ar = [m_a * R(T₁ - T₂)]/(γ - 1)
W_ar = [0.1 * 0.208(300 - 320)]/(1.67 - 1)
W_ar = -0.6028 kJ
Work done by nitrogen will be;
W_n = |W_ar| + (m_p * g * m_a)/1000
W_n = 0.6028 + (5 * 9.81 * 0.1)/1000
W_n = 0.6257 kJ
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