Answer:
96 inches squared or [tex]96in^{2}[/tex]
Step-by-step explanation:
So I'm assuming that the figure shown is the fragment that is left because it doesn't exactly say what it is.
The area of a rectangle is length times width, so to the area of the original manuscript is....
A=lw
A=20(12)
A=240
You get 20 from the question and 12 from the figure.
Next, you should find the area of the fragment that is left. I would split it up into two shapes, a triangle and recitable, since right now it's a weird looking shape. The area of a triangle is base time height divided by 2....
A=[tex]\frac{bh}{2}[/tex]
The base is 12 because 18-6=6 and the height is 12 because is the width of the original rectangle. (I suggest making a line in between fragment to spilt it into two shapes or even re-drawing it to see it more clearly.) Therefore plugging everything into the equation....
A=[tex]\frac{12(12)}{2}[/tex]
A=[tex]\frac{144}{2}[/tex]
A=72
Now to find the area of the rectangle of the fragment that is left over, use the the same equation from above that was used to find the area of a rectangle and just plug in the numbers 12 and 6 because you can use the number on the top and the number on the side of the figure
A=12(6)
A=72
The final step is to subtract the area of the smaller rectangle and triangle from the original manuscript
240-72-72=96
Therefore the answer is [tex]96in^{2}[/tex]. Hope this helps. : )
