Determine the area of the archway with a semicircle top arch and two rectangular pillars. The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle with radius meters minus a semicircle with radius 3 meters. The area of the archway is (π 24) square meters.

Respuesta :

The archway is a combination of a semi-circle and two rectangles. Then the area of the archway is 13.5π + 24 square units.

What is Geometry?

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The archway with a semicircle top arch and two rectangular pillars. The lower supports are and the area of the two supports is square meters.

The upper arch can be decomposed as one semicircle with radius meters minus a semicircle with a radius of 3 meters.

The archway is a combination of a semi-circle and two rectangles.

Area of archway = 2 × Area of rectangle + Area of a semicircle

Area of semicircle will be

[tex]\rm Area\ of\ semicircle = \dfrac{1}{2} \pi (r_2^2-r_1^2)\\\\Area\ of\ semicircle = \dfrac{1}{2} \pi (6^2 - 3^2)\\\\Area\ of\ semicircle = \dfrac{1}{2} \pi (36-9)\\\\Area\ of\ semicircle =\dfrac{1}{2}* 27 \ \pi \\\\Area\ of\ semicircle = 13.5 \ \pi[/tex]

The area of the rectangle will be

[tex]\rm Area\ of\ rectangle = Length * Width \\\\Area\ of\ rectangle = 3*4\\\\Area\ of\ rectangle = 12[/tex]

Then the area of the archway will be

Area of archway = 2 × 12 + 13.5π

Area of archway = 13.5π + 24

More about the geometry link is given below.

https://brainly.com/question/7558603

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Answer:

congruent rectangles, 24, 6, & 13.5

Step-by-step explanation:

i did it

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