how do you find the legs of a right triangle when only given the hypotenuse?
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Answer:
We know that a^2+b^2=c^2. The 45° angle lets us know that y=x (45+45+90=180), so the problem is y^2+x^2=4sqrt of 2
[tex]4 \sqrt{2} = \sqrt{32 } \\ \sqrt{32} ^{2} = 32[/tex]
So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be 4 for both x and y
Step-by-step explanation:
let me know if I'm wrong lol