hello help me with this question thanks in advance
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Answer:
See below.
Step-by-step explanation:
1) Piece lengths are:
=> 4 cm
=> 8 cm
=> 16 cm
2) Meters of curtain in bundles are :
=> 120 m
=> 300 m
=> 420 m
[tex]\bold{\huge{\underline{ Solution 1 }}}[/tex]
Let the given ratios be 1x, 2x and 4x
According to the question,
[tex]\sf{ x + 2x + 4x = 28}[/tex]
[tex]\sf{ 7x = 28}[/tex]
[tex]\sf{ x = }{\sf{\dfrac{28}{7}}}[/tex]
[tex]\sf{ x = }{\sf{\cancel{\dfrac{28}{7}}}}[/tex]
[tex]\bold{ x = 4}[/tex]
Thus, The value of x is 4
Length of first piece = 4 cm
Length of second piece
[tex]\sf{ = 2}{\sf{\times{4}}}[/tex]
[tex]\bold{ = 8\: cm }[/tex]
Length of third piece
[tex]\sf{ = 4}{\sf{\times{4}}}[/tex]
[tex]\bold{ = 16 \:cm }[/tex]
Hence, The length of each piece of board is 4 cm , 8cm and 16cm .
[tex]\bold{\huge{\underline{ Solution 2 }}}[/tex]
Let the given ratios be 2x, 5x and 7x
According to the question,
[tex]\sf{ 2x + 5x + 7x = 840}[/tex]
[tex]\sf{ 14x = 840}[/tex]
[tex]\sf{ x = }{\sf{\dfrac{840}{14}}}[/tex]
[tex]\sf{ x = }{\sf{\cancel{\dfrac{840}{14}}}}[/tex]
[tex]\bold{ x = 60}[/tex]
Thus, The value of x is 60
Length of the first bundle of curtains
[tex]\sf{ = 2}{\sf{\times{60}}}[/tex]
[tex]\bold{ = 120\: m }[/tex]
Length of the second bundle of curtains
[tex]\sf{ = 5}{\sf{\times{60}}}[/tex]
[tex]\bold{ = 300\ : m }[/tex]
Length of the third bundle of curtains
[tex]\sf{ = 7 }{\sf{\times{60}}}[/tex]
[tex]\bold{ = 420\: m }[/tex]
Hence, The length of each bundle of curtains is 120m, 300 m and 420 m