h(x) = x + 3
3. h(-7) =
![hx x 3 3 h7 class=](https://us-static.z-dn.net/files/d0e/3780e2532cbdee3da7ad47e004e517fb.png)
h(x) = x+3-----(1)
put your value (-7)
into equ. (1) as x
h(-7) = 7+3
h(-7) =10