Question

how do you get 1.8 from$f(2)=\frac{2}{1+e^{-(2)} }$

Answer 1

Answer:

see explanation

Step-by-step explanation:

$\frac{2}{1+e^{-2} }$ ← evaluate $e^{-2}$ using calculator

= $\frac{2}{1+0.135}$

= $\frac{2}{1.135}$

= 1.762.....

≈ 1.8 ( to 1 dec. place )