Question

Help please I don't know how to do this and it is due soon!!
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Answer 1

Answer:

• its an isosceles triangle

• not a right angle triangle.

part A:

$\sf AB^2 = (-2-1)^2 + (1+3)^2$

$\sf AB^2 =25$

$\sf AB =5$

$\sf AC^2 = (2-1)^2 + (4+3)^2$

$\sf AC^2 = 50$

$\sf AC = \sqrt{50}$

$\sf AC = 5\sqrt{2}$

$\sf BC^2 = (2--2)^2 + (4-1)^2$

$\sf BC^2 = 25$

$\sf BC = 5$

use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50

Answer 2

It's isosceles

• A(-3,1)
• B(1,-2)
• C(4,2)

$\\ \rm\hookrightarrow AB=\sqrt{(-2-1)^2+(1+3)^2}=\sqrt{9+16}=\sqrt{25}=5$

$\\ \rm\hookrightarrow BC=\sqrt{(2+2)^2+(4-1)^2}=\sqrt{16+9}=5$

$\\ \rm\hookrightarrow AC=\sqrt{(4+3)^2+(2-1)^2}=\sqrt{50}$

• AB=BC

Its isosceles