Respuesta :

  • 2x^2+5x-4=0

[tex]\\ \rm\hookrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{-5\pm\sqrt{25+32}}{4}[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{-5\pm\sqrt{57}}{4}[/tex]

ACCESS MORE