Answer:
[tex]x=6,[/tex] or [tex]x=\frac{-11}{2}[/tex]
Step-by-step explanation:
Given: [tex]l=x+2[/tex] [tex]b=2x-5[/tex]
Area = [tex]56[/tex]
find: find [tex]x[/tex]
Solution: Since
[tex]A=L[/tex] [tex]b=56[/tex]
Hence
l [tex]b=56[/tex]
[tex](x+2)(2x-5)=56[/tex]
[tex]2x^{2} -5x+4x-10=56[/tex]
[tex]2x^{2} -x-10-56=0[/tex]
[tex]2x^{2} -x-66=6[/tex]
[tex]x=\frac{1+\sqrt{1-4\times2(-66)}}{4}[/tex]
[tex]l=\frac{1+\sqrt{1+520} }{4}=\frac{1+23}{4}[/tex]
[tex]k=\frac{24}{4}[/tex] or [tex]x=\frac{-22}{4}[/tex]
Hence
Answer: [tex]x=6,[/tex] or [tex]x=\frac{-11}{2}[/tex]
I hope this helps you
:)
