Respuesta :

answer:

there will be $2346.40 after 4 years.

explanation:

[tex]\sf A = P(1 + \frac{r}{n} )^{nt}[/tex]

"A" - money after compound interest, "P" - money deposited, "r" - rate of interest, "t" - time (years)

given:

  • P = $2000
  • r = 4%
  • t = 4 years

using the formula:

[tex]\sf A = 2,000(1 + \frac{0.04}{12} )^{12*4}[/tex]

[tex]\sf A = 2,346.40[/tex]

'compounded monthly so n will be 12 months'

Answer:

$2,346.40 (nearest cent)

Step-by-step explanation:

[tex]B = P(1 + \frac{r}{n})^{nt}[/tex]

where B is the balance, P is the principal amount, r is the interest rate in decimal format, t is the time in years and n is the number of times interest is compounded per year

  • P = 2000
  • r = 4% = 4/100 = 0.04
  • n = 12
  • t = 4

[tex]\implies B = 2000(1 + \frac{0.04}{12})^{4\times12}[/tex]

[tex]\implies B = \$2346.40[/tex]

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