Respuesta :
answer:
there will be $2346.40 after 4 years.
explanation:
[tex]\sf A = P(1 + \frac{r}{n} )^{nt}[/tex]
"A" - money after compound interest, "P" - money deposited, "r" - rate of interest, "t" - time (years)
given:
- P = $2000
- r = 4%
- t = 4 years
using the formula:
[tex]\sf A = 2,000(1 + \frac{0.04}{12} )^{12*4}[/tex]
[tex]\sf A = 2,346.40[/tex]
'compounded monthly so n will be 12 months'
Answer:
$2,346.40 (nearest cent)
Step-by-step explanation:
[tex]B = P(1 + \frac{r}{n})^{nt}[/tex]
where B is the balance, P is the principal amount, r is the interest rate in decimal format, t is the time in years and n is the number of times interest is compounded per year
- P = 2000
- r = 4% = 4/100 = 0.04
- n = 12
- t = 4
[tex]\implies B = 2000(1 + \frac{0.04}{12})^{4\times12}[/tex]
[tex]\implies B = \$2346.40[/tex]