Respuesta :
The molecular formula is the expression of the number of atoms of the elements and the chemical symbols of the atoms. The correct molecular formula of the compound is [tex]\rm C_{6}H_{6}O_{6}.[/tex]
What is the molecular formula?
A molecular formula is a depiction of the chemical symbols of the elements with the number of atoms in the subscripts present in the compound.
Let the empirical formula for the compound be, [tex]\rm (CHO)_{n}[/tex] and the molar mass of the compound is 176.124 g/mole.
The percentage of the carbon in the compound is calculated as,
[tex]\begin{aligned} &=\dfrac{\text{mass of the carbon}}{\text{mass of the sample}} \times 100\\\\&= \dfrac{283.4}{692.5}\times 100\\\\&= 40.92\end{aligned}[/tex]
The percentage of the hydrogen in the compound is calculated as,
[tex]\begin{aligned} &=\dfrac{\text{mass of the hydrogen}}{\text{mass of the sample}} \times 100\\\\&= \dfrac{31.7}{692.5}\times 100\\\\&= 4.57\end{aligned}[/tex]
The percentage of the oxygen in the compound is calculated as,
[tex]\begin{aligned} &=\dfrac{\text{mass of the oxygen}}{\text{mass of the sample}} \times 100\\\\&= \dfrac{377.4}{692.5}\times 100\\\\&= 54.49\end{aligned}[/tex]
The ratio of the atomic number of the carbon in the compound is = 3.410
The ratio of the atomic number of the hydrogen in the compound is = 4.577
The ratio of the atomic number of the oxygen in the compound is = 3.406
Now dividing all the three ratios with the smallest ratio we get C: H: O = 1:1:1
Hence, the empirical formula of the compound is given as, [tex]\rm [CHO]_{n}[/tex] and the molecular formula as,
[tex]\begin{aligned}\rm 12n + 1n + 16n & = 176.24\\\\29 \rm n &= 176.24\\\\\rm n &= 6 \end{aligned}[/tex]
Hence, the molecular formula of the compound is option C. [tex]\rm C_{6}H_{6}O_{6}.[/tex]
Learn more about molecular formulas here:
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