Ms. Patterson will take t>2.5 hours to burn 590 calories riding her bike at the same rate which is 236 calories every hour.
Given that -
she burns 236 calories in 1 hour get = [tex]\dfrac{1}{236}[/tex] hours
so time taken to burn 590 calories at same rate = [tex]590 \times\dfrac{1}{236}[/tex] hours
so time taken to burn 590 calories at same rate = 2.5 hours
hence Ms. Patterson will take t>2.5 hours to burn 590 calories riding her bike at the same rate which is 236 calories every hour.
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