Ms. Patterson burns 236 calories riding her bike every hour. She wants to burn more than 590 calories riding her bike at the same rate. Which inequality represents all possible values for t, the number of hours Ms. Gallegos must ride her bike to burn more than 590 calories? Question 1 options: t > 2. 5 t < 2. 5 t >0. 4 t < 0. 4.

Respuesta :

Ms. Patterson will take t>2.5 hours to burn 590 calories  riding her bike at the same rate which is 236 calories every hour.

What amount of time Ms. Patterson  will take to burn more then 590 ?

Given that -

she burns 236 calories in 1 hour get = [tex]\dfrac{1}{236}[/tex] hours

so time taken to burn 590 calories at same rate  = [tex]590 \times\dfrac{1}{236}[/tex]  hours

so time taken to burn 590 calories at same rate  = 2.5 hours

hence Ms. Patterson will take t>2.5 hours to burn 590 calories  riding her bike at the same rate which is 236 calories every hour.

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