Question

Phone calls arrive at the rate of 48 per hour at the reservation desk for regional airways.

A) Compute the probability of receiving three calls in a 10-minute interval of time?(to 4 decimals)

B) Compute the probability of receiving exactly 13 calls in 15 minutes. (To 4 decimals)

C) Suppose no calls are currently on hold. If an agent takes 10 minutes to complete the current call, how many callers do you expect to be waiting by that time?

D) What is the probability that none will be waiting?

E) If no calls are being processed, what is the probability that the agent can take 5 minutes for a personal time without being interrupted by a call?

Answer 1

The different probabilities and number of callers expected to be waiting are;

A) P(x = 3) = 0.0286

B) P(x = 13) = 0.1056

C) 8 will be waiting

D) P(x = 0) = 0.0003

E) P(x = 0) = 0.0067

How to find probability using Poisson distribution?

We are given the rate of 48 phone calls per hour.

Thus, we will use poisson's distribution formula;

P(x) = (λˣ × e^(-λ))/x!

A) Probability of receiving three calls in a 10-minute interval of time which is P(x = 3). Thus;

λ = 48 * (10/60)

λ = 8

P(x = 3) = (8³ × e⁻⁸)/3!

P(x = 3) = 0.0286

B) Probability of receiving exactly 13 calls in 15 minutes is P(x = 13). Thus;

λ = 48 * (15/60)

λ = 12

P(x = 13) = (12¹³ × e⁻¹²)/13!

P(x = 13) = 0.1056

C) No calls are currently on hold and it takes 10 minutes to complete one call. Thus;

λ = 48 * (10/60)

λ = 8

Thus, 8 will be waiting after 10 minutes.

D) Probability that no one will be waiting is;

P(x = 0) = (8⁰ × e⁻⁸)/0!

P(x = 0) = 0.0003

E) No calls being processed and it takes 5 minutes for a personal time without being interrupted by a call. Thus;

λ = 48 * (5/60)

λ = 4

P(x = 0) = (4⁰ × e⁻⁵)/0!

P(x = 0) = 0.0067

Read more about probability with poisson's distribution at; https://brainly.com/question/7879375