Question

Factor completely 18x2 − 21x −15. 3(2x 1)(3x − 5) 3(2x − 5)(3x 1) 3(2x − 1)(3x 5) 3(6x 1)(x − 5).

Answer 1

The factor of the $18x^{2} -21x-15$ will be 3(3x-5)(2x+1).

What will be the factor of  $18x^{2} -21x-15$ ?

Given quadratic equation is $18x^{2} -21x-15$

By taking 3 common from whole of the equation it becomes.

$3(6x^{2} -7x-5)$

now by factorization equation will be.

$3(6x^{2} -10x+3x-5)$

3[(2x(3x-5)+1(3x-5)]

Taking (3x-5) common from whole equation it will become

3(3x-5)(2x+1).

Hence the factor of the $18x^{2} -21x-15$ will be 3(3x-5)(2x+1).

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